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Tổng dòng/cột max, dòng có nhiều số nguyên tố trong mảng 2 chiều

10cth1-2 July 30, 2011 Nam Le 0

Thao tác trên mảng 2 chiều:

[codes=c]#include “stdio.h”
#include “conio.h”
#include “math.h”
#define row 100
#define col 100

void nhapmang(int a[][col],int dong, int cot)
  for(int i=0; i    for(int j=0; j      {
        printf(“NHap phan tu cua mang: a[%d][%d]”,i, j);

void xuatmang(int a[][col],int dong, int cot)
  for(int i=0; i     {
      for(int j=0; j        printf(“%4d”, a[i][j]);


long tongdong(int a[][col],int cot,int i)
  long s=0;
  for(int j=0; j  {
  return s;

int timdongmax(int a[][col], int dong, int cot)
  int vt=0;
  for( int i=0;i    for( int j=0; j       {
  return vt;

long cotmax(int a[][col], int dong,int j)
  long scot=0;
  for(int i=0; i    scot+=a[i][j];
  return scot;

int timcotmax(int a[][col],int dong, int cot)
  int vtcot=0;
  for(int i=0; i    for(int j=0; j      {
        if(cotmax(a, dong, j)>cotmax(a, dong, vtcot))
  return vtcot;

int ktnt(int p)
  if(p<2) return 0;
  for(int u=2; u<=sqrt(p); u++)
      return 0;
  return 1;

int demdongngto(int a[][col], int cot, int i)
  int demdong=0;
  for(int j=0; j    {
  return demdong;

int tim_dong_nh_nt(int a[][col], int dong, int cot)
  int vtdong=0;
  for(int i=0; i    for(int j=0;j      {
        if(demdongngto(a, cot, i)>demdongngto(a, cot, vtdong))
  return vtdong;

void main()
  int a[row][col],dong,cot;
  printf(“Nhap vao so dong”); scanf(“%d”,&dong);
  printf(“Nhap vao so cot”); scanf(“%d”,&cot);
  nhapmang(a, dong, cot);
  printf(“Mang vua nhap la \n”);
  xuatmang(a, dong, cot);
  int kq1= timdongmax(a, dong, cot);
  printf(“Dong co tong lon nhat la %d \n”,kq1);
  int kq2= timcotmax(a, dong, cot);
  printf(“Cot co tong lon nhat la %d \n”,kq2);
  int kq3= tim_dong_nh_nt(a, dong,cot);
  printf(“Dong co nhieu co nguyen to la %d \n”, kq3);

Last modified on December 9th, 2020 at 1:28 am

Nam Le

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